알고리즘:bfs 색칠하기
0으로 둘러 쌓인 1로 이루어진 곳에 다른 숫자 채우기
bfs3.txt
7
0 1 1 0 1 0 0
0 1 1 0 1 0 1
1 1 1 0 1 0 1
0 0 0 0 1 1 1
0 1 0 0 0 0 0
0 1 1 1 1 1 0
0 1 1 1 0 0 0
------------------------------------------------
#include <stdio.h>
typedef struct _path{
int x;
int y;
int length;
} Path;
Path que[100];
int n;
int map[100][100];
int front = 0;
int rear = 0;
int count = 1;
int ans = 100;
void enque(int x, int y, int c){
que[rear].x = x;
que[rear].y = y;
que[rear].length = c +1;
rear ++;
map[y][x] = c;
}
void bfs3(int x, int y, int c){
map[y][x] = c;
que[rear].x = x;
que[rear].y = y;
que[rear].length = count;
rear++;
Path path;
while(front < rear){
path = que[front++];
if (path.y -1 >= 0 && map[path.y -1][path.x] == 1){
enque(path.x, path.y -1, c);
}
if (path.y +1 < n && map[path.y +1][path.x] == 1){
enque(path.x, path.y+1, c);
}
//left
if (path.x-1 >= 0 && map[path.y][path.x-1] == 1){
enque(path.x-1, path.y,c);
}
//right
if (path.x+1 < n && map[path.y ][path.x+1] == 1){
enque(path.x+1, path.y, c);
}
}
}
void printmap(){
printf("-------------------------------\n");
for(int i =0 ; i < n; i++){
for(int j = 0 ; j < n ; j++){
printf("%d", map[i][j]);
}
printf("\n");
}
}
int main()
{
int start;
int v1, v2;
freopen("bfs3.txt","r",stdin);
scanf("%d", &n);
for(int i =0 ; i < n; i++){
for(int j = 0 ; j < n ; j++){
scanf("%d", &map[i][j]);
}
}
printmap();
int color = 2;
for (int i = 0; i < n ; i ++){
for(int j = 0; j < n ; j++){
if(map[i][j] == 1){
bfs3(j,i, color++);
}
}
}
printf("answer %d\n", color-2);
printmap();
return 0;
}
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